![](/img/cover-not-exists.png)
Another Way to Discover That$\sum\limits^\infty_{n = 1}\frac{1\cdot 3\cdot 5\cdots (2n - 1)}{n2^{n+1}n!} = ln 2$
David CallanVolume:
58
Language:
english
Journal:
Mathematics Magazine
DOI:
10.2307/2690177
Date:
November, 1985
File:
PDF, 274 KB
english, 1985