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Cryptography and Communications 2020 / 2

Solving x+x2l+⋯+x2ml=a$x+x^{2^{l}}+\cdots +x^{2^{ml}}=a$ over F2n$\mathbb {F}_{2^{n}}$

Mesnager, Sihem, Kim, Kwang Ho, Choe, Jong Hyok, Lee, Dok Nam, Go, Dae Song
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Journal:
Cryptography and Communications
DOI:
10.1007/s12095-020-00425-3
Date:
February, 2020
File:
PDF, 271 KB
2020
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